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The equation abs(x+1) abs(x-1)=a^2-2a-3 ...

The equation `abs(x+1) abs(x-1)=a^2-2a-3` can have real solutions for x if 'a' belongs to

A

`(-infty,-1)cup[3,infty)`

B

`[1-sqrt5,1+sqrt5]`

C

`[1-sqrt5,-1]cup[3,1+sqrt5]`

D

both (1) and (3)

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The correct Answer is:
A
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