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Let S=8/5+16/65+......128/(2^18+1) then...

Let `S=8/5+16/65+......128/(2^18+1)` then

A

S=1088/545

B

S=545/1088

C

S=1056/545

D

S=545/1056

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The correct Answer is:
A
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PATHFINDER-PROGRESSION AND SERIES -QUESTION BANK
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