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If alpha+beta =(pi/2) and beta+gamma=alp...

If `alpha+beta =(pi/2)` and `beta+gamma=alpha`, then the `tanalpha` equals:

A

`2(tanbeta+tangamma)`

B

`tanbeta+tangamma`

C

`tanbeta+2tangamma`

D

`2tanbeta+tangamma`

Text Solution

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The correct Answer is:
C
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