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If sec(theta+alpha)+sec(theta-alpha)=2/c...

If `sec(theta+alpha)+sec(theta-alpha)=2/costheta`. then `cos^2theta` is equal to

A

`1-cosalpha`

B

`1+cosalpha`

C

`sinalpha`

D

`1-sinalpha`

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The correct Answer is:
B
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