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The expression 3{sin^4((3pi/2)-alpha)+si...

The expression `3{sin^4((3pi/2)-alpha)+sin^4(3pi-alpha)} -2{sin^6(pi/2+alpha)+sin^6(5pi-alpha)}` is equal to

A

0

B

1

C

3

D

`sin 4alpha=cos 6alpha`

Text Solution

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The correct Answer is:
B
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Show that 3{sin^4((3pi)/2-alpha)+sin^4(3pi+alpha)}-2{sin^6(pi/2+alpha)+ sin^6(5pi-alpha)}=1

Prove that, 3[sin^(4)((3pi)/2 - alpha) + sin^(4)(3pi + alpha)] - 2[sin^(6)((pi)/2 + alpha) + sin^(6) (5pi - alpha)] = 1

Knowledge Check

  • If (cos^4 alpha)/(cos^2 beta) + (sin^4 alpha)/(sin^2 alpha) -

    A
    2
    B
    3
    C
    4
    D
    1

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