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If x=secphi-tanphi and y=cosecphi+cotphi...

If `x=secphi-tanphi` and `y=cosecphi+cotphi`, then

A

`x=(y+1)/(y-1)`

B

`x=(y-1)/(y+1)`

C

`y=(1+x)/(1-x)`

D

xy+x-y+1=0

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The correct Answer is:
B, C, D
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PATHFINDER-TRIGONOMETRIC RATIOS AND IDENTITIES-QUESTION BANK
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