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If Pn=sin^ntheta+cos^ntheta where n in W...

If `P_n=sin^ntheta+cos^ntheta` where `n in W` (whole number)and `theta in R (real number)`
if `P_1=m` then the value of `4(1-P_6)` is

A

`3(m-1)^2`

B

`3(m^2-1)^2`

C

`3(m+1)^2`

D

`3(m^2+1)^2`

Text Solution

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The correct Answer is:
B
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