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If sintheta=(2t)/(1+t^2) and theta lies ...

If `sintheta=(2t)/(1+t^2)` and `theta` lies in the second quadrant then `costheta` is equal to

A

`(1-t^2)/(1+t^2)`

B

`(t^2-1)/(1+t^2)`

C

`-abs(1-t^2)/(1+t^2)`

D

`(1+t^2)/abs(1-t^2)`

Text Solution

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The correct Answer is:
C
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