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cot^-1 (9/2) + cot^-1 (25/2) + cot^-1 (4...

`cot^-1 (9/2) + cot^-1 (25/2) + cot^-1 (49/2) + ........` to n terms is equal to

A

`tan^-1 (2n/(4n + 5))`

B

`cot^-1 (2n/(4n + 5))`

C

`tan^-1 (2n/(4n + 3))`

D

`cot^-1 (2n/(4n + 3))`

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The correct Answer is:
A
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PATHFINDER-TRIGONOMETRIC EQUATION AND INVERSE-QUESTION BANK
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