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f(x)=sin{cot^-1(x+1)}-cos(tan^-1x) a=cos...

`f(x)=sin{cot^-1(x+1)}-cos(tan^-1x)`
`a=costan^-1sincot^-1x`
`b=cos(2cos^-1x+sin^-1x)`
Answer the following question on above passage:
The value of x for which f(x)=0 is

A

-0.5

B

0

C

44198

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
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