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If sin^-1x+sin^-1y+sin^-1z=(3pi)/2, then...

If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2`, then the value of `x^9+y^9+z^9-1/(x^9y^9z^9)` is equal to

A

0

B

1

C

2

D

3

Text Solution

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The correct Answer is:
C
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PATHFINDER-TRIGONOMETRIC EQUATION AND INVERSE-QUESTION BANK
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