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The equation of the locus of points equi...

The equation of the locus of points equidistant from (-1,-1) and (4, 2) is :

A

3x -5y - 7 =0

B

5x + 3y -9 = 0

C

4x + 3y -2 = 0

D

x - 3y + 5 = 0

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The correct Answer is:
B
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PATHFINDER-CARTESIAN COORDINATES AND STRAIGHT LINE-QUESTION BANK
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