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If the lines ax+by+c=0, bx+cy+a=0 and Cx...

If the lines ax+by+c=0, bx+cy+a=0 and Cx+ay+b=0 are concurrent `(a+b+cne0)` then

A

`a^3+b^3+c^3-3abc=0`

B

a=b

C

a=b=c

D

`a^2+b^2+c^2-bc-ca-ab=0`

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The correct Answer is:
A, C, D
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