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The vertices of a triangle are A(x1,x1ta...

The vertices of a triangle are `A(x_1,x_1tanalpha),(Bx_2,x_2tanbeta)` and `C(x_3,x_3tangamma)`. If the circumcentre of `triangle ABC` coincides with the origin and H(a,b) be its orthocentre, then a/b is equal to

A

`(cosalpha+cosbeta+cosgamma)/(cosalphacosbetacosgamma)`

B

`(sinalpha+sinbeta+singamma)/(sinalphasinbetasingamma)`

C

`(tanalpha+tanbeta+tangamma)/(tanalphatanbetatangamma)`

D

`(cosalpha+cosbeta+cosgamma)/(sinalpha+sinbeta+singamma)`

Text Solution

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The correct Answer is:
D
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