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If e^(ialpha)=cosalpha+isinalpha, then f...

If `e^(ialpha)=cosalpha+isinalpha`, then for the `DeltaABC`, the value of `e^((iA)/2)e^((iB)/2)e^((iC)/2)=`

A

i

B

-i

C

1

D

-1/i

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A, D
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