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The roots of the equation Z^3+1=0 are ca...

The roots of the equation `Z^3+1=0` are called cube roots of unity.Clearly Z=-1 is a root and the other roots are complex comjugate root and they are `omega=cos((2pi)/3) +isin((2pi)/3)` and `omega^2=cos((4pi)/3)+isin((4pi)/3)`
`1+omega+omega^2=0`
`(1+omega^2)^7+(1+omega)^7` equals

A

0

B

(-1)

C

1

D

1

Text Solution

Verified by Experts

The correct Answer is:
B
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