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1/(n!)+1/(2!(n-2)!)+1/(4!(n-4)!)+ …… is ...

`1/(n!)+1/(2!(n-2)!)+1/(4!(n-4)!)+ ……` is equal to

A

`2^(n-1)/(n!)`

B

`2^n/((n+1)!)`

C

`2^n/(n!)`

D

`2^(n-2)/((n-1)!)`

Text Solution

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The correct Answer is:
A
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PATHFINDER-BINOMIAL THEOREM-QUESTION BANK
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