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Let an=(1000)^n/(n!) for n in N. Then an...

Let `a_n=(1000)^n/(n!)` for `n in N`. Then `a_n` is greatest, when

A

n=998

B

n=999

C

n=1000

D

n=1001

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The correct Answer is:
B, C
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PATHFINDER-BINOMIAL THEOREM-QUESTION BANK
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  3. Let an=(1000)^n/(n!) for n in N. Then an is greatest, when

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  8. Let P=sum(r=1)^(50)((50+r)Cr(2r-1))/((50)Cr(50+r)), Q=sum(r=1)^(50)(50...

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  9. In reference to the expansion (1+x)^n=sum(r=0)^nCrx^r, n in N, match t...

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  11. Match List - I with List-II

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