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In a DeltaABC, b^2+c^2=1999a^2, then (c...

In a `DeltaABC,` `b^2+c^2`=`1999a^2,` then `(cotB+cotC)/cotA` is equal to

A

`1/999`

B

36161

C

999

D

1999

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A
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PATHFINDER-SOLUTION OF TRIANGLE AND HEIGHT AND DISTANCE-QUESTION BANK
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