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In aDeltaABC,sinA/sinC=sin(A-B)/sin(B-C)...

In a`DeltaABC,sinA/sinC=sin(A-B)/sin(B-C)`then

A

cotA,cotB,cotC, in A.P.

B

sin2A,sin2B,sin2C in A.P.

C

cos2A,cos2B,cos2C in A.P.

D

asinA,bsinB,csinC in A.P.

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The correct Answer is:
C
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PATHFINDER-SOLUTION OF TRIANGLE AND HEIGHT AND DISTANCE-QUESTION BANK
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