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If in a DeltaABC, CD is the angle bisect...

If in a `DeltaABC,` CD is the angle bisector of the `angleABC,` then CD is equal to

A

`((a+b)/(2ab))cos (c/2)`

B

`((a+b)/(ab))cos (c/2)`

C

`((2ab)/(a+b))cos (c/2)`

D

`(bsinA)/sin(B)`

Text Solution

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The correct Answer is:
C
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PATHFINDER-SOLUTION OF TRIANGLE AND HEIGHT AND DISTANCE-QUESTION BANK
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