In a ` Delta,` (a+b+c)(b+c-a)=`lambdabc,` when`lambda inI,` then greatest value of `lambda` is

In a triangle ABC, (a+b+c)(b+c-a)=kbc if

If a, b, c are in HP and if ((a + b)/(2a - b)) + ((c + b)/(2c - b)) gt sqrt(lambdasqrt(lambdasqrt(lambda ....infty))) , then the value of lambda must be

If B(1,3) be equidistant from the point A(6,-1) and C(lambda,8) , then the value of lambda is /are -

If int (dx)/(1+sinx) = tan (x/2 - pi/lambda) + b , then the value of lambda is -

If |{:(-a^2," "ab," "ac),(" "ab,-b^2," "bc),(" "ac," "bc,-c^2):}|=lambdaa^2b^2c^2, then find the value of lambda

S , T are two foci of an ellipse and B is a one end point of minor axis . If STB be a equilateral triangle and eccentricity of the ellipse be (1)/(lambda) , then the value of lambda is _

If a \ "a n d" \ c are unit vectors and |b|=4 . The angle between a and c is cos^(-1)(1//4) and a xx b=2a xx c then, b-2c=lambdaadot The value of lambda is

Let vec a , vec ba n d vec c be three verctors such that vec a!=0,| vec a|=| vec c|=1,| vec b|=4 and | vec bxx vec c|=sqrt(15)dot If vec b-2 vec c=lambda vec a , then find the value of lambda

If vec a=a_1 hat i+a_2 hat j+a_3 hat k ; vec b=b_1 hat i+b_2 hat j+b_3 hat k , . vec c=c_1 hat i+c_2 hat j+c_3 hat k and [3 vec a+ vec b """ 3 vec b+ vec c """" 3 vec c+ vec a]=lambda[vec a vec b vec c] , then find the value of lambda/4 .

A family of curve S is given by S -= x^(2) +2xy +y^(2)-4x(1-lambda) - 4y (1+lambda) +4 , then S = 0 represents (a) pair of straight line AA lambda in R (b) straight line for exactly one value of lambda (c) parabola AA lambda in R -{0} (d) ellipse for three values of lambda