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In a triangle ABC, angleB = pi/3 and ang...

In a triangle ABC, `angleB = pi/3` and `angleC= pi/4`. Let D divide side BC internally in the ratio 1:3.
Then `sin(angleBAD)/sin(angleCAD)`is

A

`1/sqrt6`

B

`1/3`

C

`1/sqrt3`

D

`sqrt(2/3`

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