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If lim(x rarr 0)[1+x ln(1+b^2)]^(1/x)=2b...

If `lim_(x rarr 0)[1+x ln(1+b^2)]^(1/x)=2b sin^2 theta, b gt 0 "and" theta in (-pi, pi]`. then the value of `theta` is

A

`+- pi/4`

B

`+- pi/3`

C

`+- pi/6`

D

`+- pi/2`

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The correct Answer is:
D
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