A circular current-carrying coil has a radius `R`. The distance from the centre of the coil, on the axis, where `B` will be `1//8` of its value at the centre of the coil is

A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis where the magnetic induction will be (1)/(8) th to its value at the centre of the coil, is

A circular current carrying coil has a radius a. Find the distance from the centre of coil, on its axis, where is the magnetic induction will be 1/6th of its value at the centre of coil.

Show that the magnetic field along the axis of a current carrying coil of radius r at a distance x from the centre of the coil is smaller by the fraction 3x^2//2r^2 than the field at the centre of the coil carrying current.

An electric current is flowing in a circular coil of radius r .If at a distance sqrt(K)r from the centre on the axis of the coil the magnetic fleld be (1)/(8) th of it's value at the centre,then find the value of K.

Radius of current carrying coil is 'R'. Then ratio of magnetic fields at the centre of the coil to the axial point, which is Rsqrt(3) distance away from the centre of the coil :-

The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at distance 'a' from centre of the coil and perpendicular to the axis of coil is

A closely wound, circular coil with radius 2.40 cm has 800 turns. (a) What must the current in the coil be if the magnetic field at the centre of the coil is 0.0580 T ? (b) At what distance x from the centre of the coil, on the axis of the coil, is the magnetic field half its value at the centre?