Elevation in boiling point was `0.52^(@)C` when 6 g of a compound X was dissolved in 100 g of water. Molecular weight of X is (`K_(b)` of water is `5.2^(@)C` per 100 g of water)

The boiling point fo water (100^(@)C become 100.52^(@)C , if 3 grams of a nonvolatile solute is dissolved in 200 ml of water. The molecular weight of solute is ( K_(b) for water is 0.6 "K.kg mol"^(-1) )

The boiling point of water (100^(@)C) becomes 100.25^(@)C if 3 gramss of a nonvolatile solute is dissolved in 200 ml of water.The molecular weight of solute is

When 0.6g of urea dissolved in 100g of water, the water will boil at (K_(b) for water = 0.52kJ. mol^(-1) and normal boiling point of water =100^(@)C) :

The boiling point of a solution made by dissolving 12.0 g of glucose in 100 g of water is 100.34^(@)C . Calculate the molecular weight of glucose, K_(b) for water = 0.52^(@)C//m .

To observe an elevation of boiling point of 0.05^(@)C , the amount of a solute (molecular weight = 100) to be added to 100 g of water (K_(b) = 0.5) is