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Calculate E("cell") at 25^(@)C for the ...

Calculate `E_("cell")` at `25^(@)C` for the reaction :
`Zn+Cu^(2+) (0.20M) to Zn^(2+) (0.50M)+Cu`
Given `E^(Theta) (Zn^(2+)//Zn)= -0.76V, E^(Theta)(Cu^(2+)//Cu)=0.34V`.

Text Solution

Verified by Experts

`E_("cell")= E_("cell")^(@)- (0.0591)/(n)log[("Product")/("Reactant")]= 0.34- (-0.76)- (0.0591)/(2)log[(Zn^(2+))/(Cu^(2+))]`
`= 1.10- (0.0591)/(2)log[(0.50)/(0.20)]`
`= 1.10- 0.02955 xx 0.3979= 1.088V`
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