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For the following cell, calculate the em...

For the following cell, calculate the emf:
`Al//Al^(3+) (0.01 M)"||" Fe^(2+) (0.02M)"|"Fe`
Given: `E_(Al^(3+)//Al)^(Theta) = -1.66V, E_(Fe^(2+)//Fe)^(Theta)= -0.44V`

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`Al//Al^(3+)(0.01M)||Fe^(2+)(0.02M)|Fe`
`E_("cell")^(@)= E_(Fe^(+2)//Fe)-E_(Al^(+3)//Al)`
`= -0.44-(-1.66)= +1.22V`
Net cell reaction:
`2Al+3Fe^(2+) to 2Al^(3+)+3Fe`
`E_("cell")= E_("cell")^(@)+ (0.0591)/(6)log(([Fe^(2+)]^(3))/([Al^(3+)]^(2)))= 1.22 + (0.0591)/(6)log (([0.02]^(3))/([0.01]^(2)))`
`= 1.22 + (0.0591)/(6)log8 xx 10^(-2)`
`1.22 + 0.00985 [log8 - 2log10]`
`= 1.22 +0.00985(0.9031-2xx1)`
`1.22 + 0.00985(-1.0969)`
`= 1.22 - 0.0108= 1.21V`
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