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Two point charge q(1)=2muC and q(2)=1muC...

Two point charge `q_(1)=2muC` and `q_(2)=1muC` are placed at distance `b=1` and `a=2cm` from the origin on the `y` and `x` axes as shown in figure .The electric field vector at point `(a),(b)` will subtend on angle `theta` with the "x-axis" given by

A

`tan theta =1 `

B

`tan theta =2`

C

`tan theta =3`

D

`tan theta =4`

Text Solution

Verified by Experts

The correct Answer is:
B
Due `q_(1)`, electric feed at `P(E_(1)) =(1)/(4pi epsilon_(0)) (q_(1))/(a^(2)) (hati)`
`q_(2)` electric fed at `P(E_(2))=(1)/(4pi epsilon_(0)) (q_(2))/(b^(2)) (hatj)`

`:.tan theta =(E_(2))/(E_(1)) =(q_(2))/(q_(1)) (a^(2))/(b^(2)) =((1)/(2)) xx ((2)/(1))^(2) =2`
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