If a constant torque of `500 N-m` turns a wheel of moment of inertia `100 kg m^(2)` about an axis passing through its centre, find the gain in angular velocity in `2 s`.

If a constant torque of 500 Nm turns a wheel of moment of inertia 100 kg m^(2) about an axis through its centre, find the gain in angular velocity in 2s.

A constant torque of 400Nm turns a wheel of moment of inertia 100kg m^(2) about an axis through its centre. The angular velocity gained in 4 second is

A constant torque of 1000 N-m turns a wheel of moment of inertia 200 kg-m^2 about an axis through its centre. Its angular velocity after 3 seconds is.

A constant torque of 200 Nm turns a wheel of moment of inertia 50 kg m^(2) about an axis through its centre. The angualr velocity 2 sec after staring form rest (in rad/sec) would be :

A costant torque of 400 N turns a flywheel at rest and of "M.I. 100 kgm"^(2) about an axis through its centre. What is the change in its angular velocity in 4 s?

If the moment of inertia of a ring about transverse axis passing through its centre is 6 kg m^(2) , then the M.I. about a tangent in its plane will be

The moment of inertia of a square plate of mass 4kg and side 1m about an axis passing through its centre and perpendicular to its plane is

Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

Calculate the moment of inertia of a ring of mass 2kg and radius 2cm about an axis passing through its centre and perpendicular to its surface.