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Let f (x)= cos (px)+ sin x be periodic, ...

Let `f (x)= cos (px)+ sin x` be periodic, then p must be : a) Positive real number b) Negative real number c) Rational d) Prime

A

Positive real number

B

Negative real number

C

Rational

D

Prime

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The correct Answer is:
To determine the value of \( p \) such that the function \( f(x) = \cos(px) + \sin(x) \) is periodic, we need to analyze the periods of the individual components of the function. ### Step-by-Step Solution: 1. **Identify the Periods of the Functions:** - The period of \( \sin(x) \) is \( 2\pi \). - The period of \( \cos(px) \) is given by \( \frac{2\pi}{p} \). 2. **Determine the Period of the Combined Function:** - The function \( f(x) \) will be periodic if the periods of both components are commensurable, meaning that their least common multiple (LCM) is finite. - Therefore, we need to find the LCM of \( 2\pi \) and \( \frac{2\pi}{p} \). 3. **Calculate the LCM:** - The LCM of \( 2\pi \) and \( \frac{2\pi}{p} \) can be expressed as: \[ \text{LCM}(2\pi, \frac{2\pi}{p}) = 2\pi \cdot \text{LCM}(1, \frac{1}{p}) = 2\pi \cdot \frac{1}{\gcd(1, \frac{1}{p})} \] - Since \( \gcd(1, \frac{1}{p}) = 1 \) for any non-zero \( p \), we have: \[ \text{LCM}(2\pi, \frac{2\pi}{p}) = 2\pi \cdot p \] 4. **Condition for Periodicity:** - For \( f(x) \) to be periodic, \( p \) must be such that \( \frac{2\pi}{p} \) is a rational number. This implies that \( p \) must be a rational number. 5. **Check the Options:** - Option (a) Positive real number: This is not sufficient alone since \( p \) could also be negative. - Option (b) Negative real number: This is not sufficient alone since \( p \) could also be positive. - Option (c) Rational: This is necessary for the periodicity of \( f(x) \). - Option (d) Prime: This is not a necessary condition for periodicity. 6. **Conclusion:** - The only condition that ensures the periodicity of \( f(x) \) is that \( p \) must be a rational number. ### Final Answer: Thus, the correct option is (c) Rational.
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