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If A={1,2,3,4} and f : A->A, then total ...

If A={1,2,3,4} and f : A->A, then total number of invertible functions,'f',such that `f(2)!=2`,`f(4)!=4`,`f(1)=1` is equal to:

A

1

B

2

C

3

D

4

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The correct Answer is:
To solve the problem, we need to find the total number of invertible functions \( f: A \to A \) under the given conditions: 1. \( f(1) = 1 \) 2. \( f(2) \neq 2 \) 3. \( f(4) \neq 4 \) Given the set \( A = \{1, 2, 3, 4\} \), we can analyze the conditions step by step. ### Step 1: Fix \( f(1) \) Since \( f(1) = 1 \), we have already determined the image of 1. The function \( f \) is now defined partially as: - \( f(1) = 1 \) ### Step 2: Determine possible values for \( f(2) \) The condition \( f(2) \neq 2 \) means that \( f(2) \) can either be 3 or 4. We will consider both cases. ### Case 1: \( f(2) = 3 \) - Now we have: - \( f(1) = 1 \) - \( f(2) = 3 \) Since \( f \) is a function from \( A \) to \( A \), the remaining values for \( f(3) \) and \( f(4) \) can only be 2 or 4. However, we also have the condition \( f(4) \neq 4 \), which means: - \( f(4) = 2 \) - Thus, \( f(3) \) must be 4. So, in this case, we have: - \( f(1) = 1 \) - \( f(2) = 3 \) - \( f(3) = 4 \) - \( f(4) = 2 \) This gives us one valid function. ### Case 2: \( f(2) = 4 \) - Now we have: - \( f(1) = 1 \) - \( f(2) = 4 \) In this case, \( f(3) \) can only be 2 or 3. However, since \( f(4) \neq 4 \), we have: - If \( f(3) = 2 \), then \( f(4) \) must be 3. - If \( f(3) = 3 \), then \( f(4) \) must be 2. So we have two subcases: 1. \( f(3) = 2 \) and \( f(4) = 3 \) 2. \( f(3) = 3 \) and \( f(4) = 2 \) Thus, we have two valid functions from this case. ### Summary of Valid Functions 1. From Case 1: - \( f(1) = 1, f(2) = 3, f(3) = 4, f(4) = 2 \) 2. From Case 2: - \( f(1) = 1, f(2) = 4, f(3) = 2, f(4) = 3 \) - \( f(1) = 1, f(2) = 4, f(3) = 3, f(4) = 2 \) ### Total Count of Invertible Functions Adding all valid functions together, we find: - 1 function from Case 1 - 2 functions from Case 2 Thus, the total number of invertible functions \( f \) is \( 1 + 2 = 3 \). ### Final Answer The total number of invertible functions \( f \) such that \( f(2) \neq 2 \), \( f(4) \neq 4 \), and \( f(1) = 1 \) is **3**.
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