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theta is said to be well behaved if it l...

`theta` is said to be well behaved if it lies in interval `[0,(pi)/(2)].` They are intelligent if they make domain of `f +g and g` equal. The vlaue of `theta` for which `h (theta)` is defined are handosome. Let
`f (x)= sqrt(thetax ^(2) -2 (theta^(2) -3) x-12theta,) g (x)=ln (x^(2) -49),`
`h (theta) ln [int_(0)^(theta) 4 cos ^(2)t dt - theta ^(2)],` where `theta` is in radians.
Complete set of vlaues of `theta` which are well behaved as well as intellignent is:

A

`[(3)/(4),(pi)/(2)]`

B

`[(3)/(5), (7)/(8)]`

C

`[(5)/(6), (pi)/(2)]`

D

`[(6)/(7) , (pi)/(2)]`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the values of \(\theta\) that are both "well behaved" and "intelligent". Let's break down the steps involved in the solution. ### Step 1: Define the Conditions for \(\theta\) 1. **Well Behaved Condition**: \[ \theta \in [0, \frac{\pi}{2}] \] 2. **Intelligent Condition**: The domain of \(f + g\) should be equal to the domain of \(g\). ### Step 2: Determine the Domain of \(g(x)\) The function \(g(x) = \ln(x^2 - 49)\) is defined when: \[ x^2 - 49 > 0 \implies |x| > 7 \] Thus, the domain of \(g\) is: \[ (-\infty, -7) \cup (7, \infty) \] ### Step 3: Determine the Domain of \(f(x)\) The function \(f(x) = \sqrt{\theta x^2 - 2(\theta^2 - 3)x - 12\theta}\) is defined when: \[ \theta x^2 - 2(\theta^2 - 3)x - 12\theta \geq 0 \] This is a quadratic inequality in \(x\). The quadratic will be defined for values of \(x\) outside its roots. ### Step 4: Find the Roots of the Quadratic To find the roots of the quadratic equation: \[ \theta x^2 - 2(\theta^2 - 3)x - 12\theta = 0 \] Using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = \theta\), \(b = -2(\theta^2 - 3)\), and \(c = -12\theta\). Calculating the discriminant: \[ D = [2(\theta^2 - 3)]^2 - 4\theta(-12\theta) = 4(\theta^2 - 3)^2 + 48\theta^2 \] ### Step 5: Set Conditions for the Roots For \(f(x)\) to be defined for all \(x\) in the domain of \(g\), the roots must be outside the intervals \((-7, 7)\). Thus, we need to ensure: 1. Both roots are less than -7 or greater than 7. ### Step 6: Analyze the Quadratic Inequality To ensure that \(f(x) \geq 0\) for \(x \in (-\infty, -7) \cup (7, \infty)\), we need to analyze the conditions on \(\theta\). 1. **Condition for Roots**: The quadratic must be positive at \(x = 7\) and \(x = -7\): - For \(x = 7\): \[ \theta(7^2) - 2(\theta^2 - 3)(7) - 12\theta \geq 0 \] - For \(x = -7\): \[ \theta(-7^2) - 2(\theta^2 - 3)(-7) - 12\theta \geq 0 \] ### Step 7: Solve the Inequalities By solving these inequalities, we can find the range of \(\theta\) that satisfies both conditions. ### Step 8: Combine Conditions Finally, we combine the conditions from the well-behaved and intelligent criteria to find the complete set of values for \(\theta\). ### Final Answer The complete set of values of \(\theta\) which are well behaved as well as intelligent is: \[ \theta \in \left[\frac{6}{7}, \frac{\pi}{2}\right] \]
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theta is said to be well behaved if it lies in interval [0,(pi)/(2)]. They are intelligent if they make domain of f +g and g equal. The vlaue of theta for which h (theta) is defined are handosome. Let f (x)= sqrt(thetax ^(2) -2 (theta^(2) -3) x-12theta,) g (x)=ln (x^(2) -49), h (theta) ln [int_(0)^(theta) 4 cos ^(2)t dt - theta ^(2)], where theta is in radians. Complete set of alues of theta which are intelligent is :

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