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Let f (x) =(2 |x| -1)/(x-3) Range of f...

Let `f (x) =(2 |x| -1)/(x-3)`
Range of `f (x):`

A

`R- {3}`

B

`(-oo, (1)/(3) ] uu (2,oo)`

C

`(-2, (1)/(3)]` uu (2,oo)`

D

R

Text Solution

AI Generated Solution

The correct Answer is:
To find the range of the function \( f(x) = \frac{2|x| - 1}{x - 3} \), we will analyze the function by considering the two cases for \( |x| \) (i.e., when \( x \geq 0 \) and \( x < 0 \)) and also the behavior of the function around the point where the denominator is zero. ### Step 1: Identify the cases for \( |x| \) The function has two cases based on the absolute value: 1. Case 1: \( x \geq 0 \) (where \( |x| = x \)) 2. Case 2: \( x < 0 \) (where \( |x| = -x \)) ### Step 2: Analyze Case 1: \( x \geq 0 \) For \( x \geq 0 \): \[ f(x) = \frac{2x - 1}{x - 3} \] We need to find the behavior of this function as \( x \) approaches different values. ### Step 3: Find limits as \( x \) approaches critical points - **At \( x = 3 \)**: The function is undefined because the denominator becomes zero. - **As \( x \) approaches 3 from the left (\( x \to 3^- \))**: \[ f(x) \to \frac{2(3) - 1}{3 - 3} \to \text{undefined (approaches } +\infty\text{)} \] - **As \( x \) approaches 3 from the right (\( x \to 3^+ \))**: \[ f(x) \to \frac{2(3) - 1}{3 - 3} \to \text{undefined (approaches } -\infty\text{)} \] ### Step 4: Find limits as \( x \to \infty \) - **As \( x \to \infty \)**: \[ f(x) \to \frac{2x - 1}{x - 3} \approx \frac{2x}{x} = 2 \] ### Step 5: Analyze Case 2: \( x < 0 \) For \( x < 0 \): \[ f(x) = \frac{-2x - 1}{x - 3} \] Again, we need to find the behavior of this function. ### Step 6: Find limits as \( x \) approaches critical points - **At \( x = 3 \)**: The function is still undefined. - **As \( x \to -\infty \)**: \[ f(x) \to \frac{-2(-\infty) - 1}{-\infty - 3} \to \frac{+\infty}{-\infty} \to 0 \] ### Step 7: Combine the results From our analysis: - As \( x \) approaches 3 from the left, \( f(x) \to +\infty \). - As \( x \) approaches 3 from the right, \( f(x) \to -\infty \). - The function approaches 2 as \( x \) approaches infinity. - The function approaches -2 as \( x \) approaches negative infinity. ### Step 8: Determine the range The range of \( f(x) \) can be summarized as: - From \( -\infty \) to \( -2 \) (not including -2), - From \( -2 \) to \( \frac{1}{3} \) (including \( \frac{1}{3} \)), - From \( 2 \) to \( +\infty \) (not including 2). Thus, the range of \( f(x) \) is: \[ \text{Range} = (-\infty, -2) \cup \left[-\frac{1}{3}, 2\right) \cup (2, +\infty) \]
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