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A batsman can score 0, 1, 2, 3, 4 or 6 r...

A batsman can score `0, 1, 2, 3, 4` or `6` runs from a ball. The number of different sequences in which he can score exactly 30 runs in an over of six balls

A

4

B

72

C

56

D

71

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of different sequences in which a batsman can score exactly 30 runs in an over of six balls, we will follow these steps: ### Step 1: Identify Possible Scores The batsman can score the following runs from a ball: 0, 1, 2, 3, 4, or 6. We need to find combinations of these scores that add up to exactly 30 runs over 6 balls. ### Step 2: List Combinations We will list the possible combinations of scores that total 30 runs: 1. **Combination 1**: 6, 6, 6, 6, 6, 0 (five 6s and one 0) 2. **Combination 2**: 6, 6, 6, 6, 4, 2 (four 6s, one 4, and one 2) 3. **Combination 3**: 6, 6, 6, 4, 4, 4 (three 6s and three 4s) 4. **Combination 4**: 6, 6, 4, 4, 3, 3 (two 6s, two 4s, and two 3s) ### Step 3: Calculate the Number of Ways for Each Combination Now we will calculate the number of different sequences for each combination using the formula for permutations of a multiset: 1. **For Combination 1**: - Sequence: 6, 6, 6, 6, 6, 0 - Number of ways = \( \frac{6!}{5! \cdot 1!} = 6 \) 2. **For Combination 2**: - Sequence: 6, 6, 6, 6, 4, 2 - Number of ways = \( \frac{6!}{4! \cdot 1! \cdot 1!} = 30 \) 3. **For Combination 3**: - Sequence: 6, 6, 6, 4, 4, 4 - Number of ways = \( \frac{6!}{3! \cdot 3!} = 20 \) 4. **For Combination 4**: - Sequence: 6, 6, 4, 4, 3, 3 - Number of ways = \( \frac{6!}{2! \cdot 2! \cdot 2!} = 90 \) ### Step 4: Sum the Ways Now, we will sum the number of ways from all combinations: - Total ways = \( 6 + 30 + 20 + 90 = 146 \) ### Final Answer The total number of different sequences in which the batsman can score exactly 30 runs in an over of six balls is **146**.
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