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The number of ways in which eight digit ...

The number of ways in which eight digit number can be formed using the digits from 1 to 9 without repetition if first four places of the numbers are in increasing order and last four places are in decreasing order is N, then find the value of `(N)/(70)`.

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The correct Answer is:
9
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number of ways in which eight digit number can be formed using the digits from 1 to 9 without repetition, if first four places of the numbers are in increasing order and last 4 places are in decreasing order , is 'n' then n/70 is equal to.

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Knowledge Check

  • Four digit numbers are formed using the digits 0, 2, 3,5 without repetition. The probability of such a number divisible by 5 is

    A
    `1/5`
    B
    `4/5`
    C
    `1/30`
    D
    `5/9`

  • The sum of 3 digits numbers that can be formed using the digits 3,4 and 5 when repetition of digits is not allowed is

    A
    2664
    B
    3882
    C
    4044
    D
    4444

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