Four couples (husband and wife) decide to form a committee of four members. The number of different committees that can be formed in which no couple find a place is `lambda`, then the sum of digits of `lambda` is :

Answer

To solve the problem of forming a committee of four members from four couples (husbands and wives) such that no couple is included in the committee, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Problem**: We have 4 couples, which means we have 4 husbands (M1, M2, M3, M4) and 4 wives (W1, W2, W3, W4). We need to select 4 members for a committee, ensuring that no couple is selected together.

2. **Choosing Members**: Since we can't have both members of a couple in the committee, we can only select one member from each couple. Thus, for each couple, we have 2 choices: we can either select the husband or the wife.

3. **Calculating the Choices**:
- For the first couple, we have 2 choices (either M1 or W1).
- For the second couple, we also have 2 choices (either M2 or W2).
- For the third couple, we have 2 choices (either M3 or W3).
- For the fourth couple, we have 2 choices (either M4 or W4).

Therefore, the total number of ways to select one member from each of the 4 couples is given by:
\[ 2 \times 2 \times 2 \times 2 = 2^4 \]

4. **Calculating \(2^4\)**:
\[ 2^4 = 16 \]
This means there are 16 different committees that can be formed under the given conditions.

5. **Finding the Sum of Digits**: Now, we need to find the sum of the digits of \( \lambda \), where \( \lambda = 16 \).
- The digits of 16 are 1 and 6.
- Therefore, the sum of the digits is:
\[ 1 + 6 = 7 \]

### Final Answer:
The sum of the digits of \( \lambda \) is **7**.