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The tangent to y = ax ^(2)+ bx + (7 )/(2...

The tangent to `y = ax ^(2)+ bx + (7 )/(2) at (1,2)` is parallel to the normal at the point `(-2,2)` on the curve `y = x ^(2)+6x+10.` Then the vlaue of `a/2-b` is:

A

2

B

0

C

3

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
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VIKAS GUPTA (BLACK BOOK) ENGLISH-APPLICATION OF DERIVATIVES -EXERCISE (SUBJECTIVE TYPE PROBLEMS)
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