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let f (x) = sin ^(-1) ((2g (x))/(1+g (x)...

let `f (x) = sin ^(-1) ((2g (x))/(1+g (x)^(2))),` then which are correct ?
(i) f (x) is decreasing if `g (x)` is increasig and `|g (x) gt 1`
(ii) `f (x)` is an increasing function if `g (x)` is increasing and `|g (x) |le 1`
(iii) f (x) is decreasing function if ` f(x)` is decreasing and `|g (x) | gt 1`

A

(i) and (iii)

B

(i) and (ii)

C

(i) (ii) and (iii)

D

(iii)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the function \( f(x) = \sin^{-1} \left( \frac{2g(x)}{1 + g(x)^2} \right) \) and determine the behavior of \( f(x) \) based on the properties of \( g(x) \). ### Step 1: Understanding the Function The function \( f(x) \) is defined as: \[ f(x) = \sin^{-1} \left( \frac{2g(x)}{1 + g(x)^2} \right) \] This expression is valid for \( |g(x)| \leq 1 \) because the range of \( \sin^{-1} \) is limited to \([-1, 1]\). ### Step 2: Analyzing the Derivative To determine whether \( f(x) \) is increasing or decreasing, we need to compute the derivative \( f'(x) \). Using the chain rule: \[ f'(x) = \frac{d}{dx} \left( \sin^{-1}(u) \right) \cdot \frac{du}{dx} \] where \( u = \frac{2g(x)}{1 + g(x)^2} \). The derivative of \( \sin^{-1}(u) \) is: \[ \frac{1}{\sqrt{1 - u^2}} \] Now, we need to find \( \frac{du}{dx} \): \[ u = \frac{2g(x)}{1 + g(x)^2} \] Using the quotient rule: \[ \frac{du}{dx} = \frac{(1 + g(x)^2)(2g'(x)) - 2g(x)(2g(x)g'(x))}{(1 + g(x)^2)^2} \] Simplifying this gives: \[ \frac{du}{dx} = \frac{2g'(x)(1 + g(x)^2 - 2g(x)^2)}{(1 + g(x)^2)^2} = \frac{2g'(x)(1 - g(x)^2)}{(1 + g(x)^2)^2} \] Thus, we have: \[ f'(x) = \frac{1}{\sqrt{1 - u^2}} \cdot \frac{2g'(x)(1 - g(x)^2)}{(1 + g(x)^2)^2} \] ### Step 3: Analyzing the Sign of \( f'(x) \) 1. **For \( |g(x)| < 1 \)**: - If \( g(x) \) is increasing (\( g'(x) > 0 \)), then \( 1 - g(x)^2 > 0 \) implies \( f'(x) > 0 \). Therefore, \( f(x) \) is increasing. 2. **For \( |g(x)| > 1 \)**: - If \( g(x) \) is increasing (\( g'(x) > 0 \)), then \( 1 - g(x)^2 < 0 \) implies \( f'(x) < 0 \). Therefore, \( f(x) \) is decreasing. ### Step 4: Evaluating the Statements Now we can evaluate the statements given in the problem: 1. **Statement (i)**: \( f(x) \) is decreasing if \( g(x) \) is increasing and \( |g(x)| > 1 \). - This is **correct** based on our analysis. 2. **Statement (ii)**: \( f(x) \) is increasing if \( g(x) \) is increasing and \( |g(x)| \leq 1 \). - This is also **correct** based on our analysis. 3. **Statement (iii)**: \( f(x) \) is decreasing if \( g(x) \) is decreasing and \( |g(x)| > 1 \). - This is **incorrect** because if \( g(x) \) is decreasing (\( g'(x) < 0 \)), then \( f'(x) \) could be positive or negative depending on the value of \( g(x) \). ### Conclusion The correct statements are: - (i) and (ii) are correct. - (iii) is incorrect.
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VIKAS GUPTA (BLACK BOOK) ENGLISH-APPLICATION OF DERIVATIVES -EXERCISE (SUBJECTIVE TYPE PROBLEMS)
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