Home
Class 12
MATHS
The equation of tangent to the circle x^...

The equation of tangent to the circle `x^2 + y^2 - 4x = 0` which is perpendicular to the normal drawn through the origin can be : (A) `x=0` (B) `x=4` (C) `x+y=2` (D) none of these

A

`x=1`

B

`x=2`

C

`x+y=2`

D

`x=4`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • CIRCLE

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise - 2 : One or More than One Answer is/are Correct|10 Videos

  • CIRCLE

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise - 3 : Comprehension Type Problems|8 Videos

  • BIONMIAL THEOREM

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise-4 : Subjective Type Problems|15 Videos

  • COMPLEX NUMBERS

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise EXERCISE-5 : SUBJECTIVE TYPE PROBLEMS|8 Videos

Similar Questions

Explore conceptually related problems

Find the equations of tangents to the circle x^2+y^2-22 x-4y+25=0 which are perpendicular to the line 5x+12 y+8=0

The equation of the tangent to the circle x^(2)+y^(2)-4x+4y-2=0 at (1,1) is

Find the equations of the tangent to the circle x^(2) + y^(2) + 2x - 2y -3= 0 which are perpendicular to 3x - y + 4 = 0

Find the equation of tangents to the ellipse 4x^(2)+5y^(2)=20 which are perpendicular to the line 3x+2y-5=0

Equation of the tangent to the circle x^(2)+y^(2)-2x+4y-4=0 which is parallel to the line 3x+4y-1=0 is

The equation of the tangent to circle x^(2)+y^(2)+2g x+2fy=0 at origin is :

The equation of the diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 which passes through origin is

Equation of the diameter of the circle x^(2) +y^(2) - 2x + 4y = 0 which passes through the origin is

Find the equation of the tangent to the circle x^2 + y^2-30x+6y+109=0 at (4, -1)

Find the equation of the tangents to the circle x^(2)+y^(2)-4x+6y-12=0 which are parallel to x+y-8=0