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The equation of diameter of a circle x^...

The equation of diameter of a circle `x^(2) + y^(2) + 2x - 4y =4`, that is parallel to `3x + 5y =4` is

A

`3x+5y=-7`

B

`3x+5y=7`

C

`3x+5y=9`

D

`3x+5y=1 `

Text Solution

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The correct Answer is:
To solve the problem of finding the equation of the diameter of the circle given by the equation \(x^2 + y^2 + 2x - 4y = 4\) that is parallel to the line \(3x + 5y = 4\), we can follow these steps: ### Step 1: Rewrite the Circle's Equation The given equation of the circle is: \[ x^2 + y^2 + 2x - 4y = 4 \] We can rewrite this in standard form by moving the constant to the other side: \[ x^2 + y^2 + 2x - 4y - 4 = 0 \] ### Step 2: Identify the Center of the Circle The general form of a circle is: \[ x^2 + y^2 + 2gx + 2fy + c = 0 \] From our equation, we can identify: - \(2g = 2\) so \(g = 1\) - \(2f = -4\) so \(f = -2\) The center of the circle \((h, k)\) is given by \((-g, -f)\): \[ \text{Center} = (-1, 2) \] ### Step 3: Find the Slope of the Given Line The equation of the line is: \[ 3x + 5y = 4 \] We can rewrite this in slope-intercept form \(y = mx + b\): \[ 5y = -3x + 4 \implies y = -\frac{3}{5}x + \frac{4}{5} \] The slope \(m\) of this line is \(-\frac{3}{5}\). ### Step 4: Find the Slope of the Diameter Since the diameter is parallel to the given line, it will have the same slope: \[ \text{Slope of diameter} = -\frac{3}{5} \] ### Step 5: Write the Equation of the Diameter Using the point-slope form of the line equation \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is the center of the circle \((-1, 2)\) and \(m = -\frac{3}{5}\): \[ y - 2 = -\frac{3}{5}(x + 1) \] ### Step 6: Simplify the Equation Now, we simplify this equation: \[ y - 2 = -\frac{3}{5}x - \frac{3}{5} \] Adding \(2\) to both sides: \[ y = -\frac{3}{5}x - \frac{3}{5} + 2 \] Convert \(2\) to a fraction: \[ 2 = \frac{10}{5} \] So: \[ y = -\frac{3}{5}x + \frac{10}{5} - \frac{3}{5} = -\frac{3}{5}x + \frac{7}{5} \] ### Step 7: Write in Standard Form To write it in standard form: \[ 3x + 5y = 7 \] Thus, the equation of the diameter of the circle that is parallel to the line \(3x + 5y = 4\) is: \[ \boxed{3x + 5y = 7} \]
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