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A foot of the normal from the point (4, ...

A foot of the normal from the point (4, 3) to a circle is (2, 1) and a diameter of the circle has the equation `2x-y-2=0`. Then the equation of the circle is :

A

`x^(2)+y^(2)-4y+2=0`

B

`x^(2)+y^(2)-4y+1=0`

C

`x^(2)+y^(2)-2x-1=0`

D

`x^(2)+y^(2)-2x+1=0`

Text Solution

Verified by Experts

The correct Answer is:
C
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