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The equation of a circle C(1) is x^(2)+y...

The equation of a circle `C_(1)` is `x^(2)+y^(2)=4`. The locus of the intersection of orthogonal tangents to the circle is the curve `C_(2)` and the locus of the intersection of perpendicular tangents to the curve `C_(2)` is the curve `C_(3)`. Then,

A

`C_(2)` is a circle

B

`C_(1), C_(2)` are circles having different centres

C

`C_(1), C_(2)` are circles having same centres

D

area enclosed between `C_(1) and C_(2)` is `8pi`

Text Solution

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The correct Answer is:
A, C, D
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