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The value of expression (1-cot23^(@))(1-...

The value of expression `(1-cot23^(@))(1-cot22^(@))` is equal to :

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To solve the expression \((1 - \cot 23^\circ)(1 - \cot 22^\circ)\), we can follow these steps: ### Step 1: Recognize the relationship between angles We know that \(23^\circ + 22^\circ = 45^\circ\). Thus, we can use the identity for cotangent: \[ \cot(45^\circ) = 1 \] This implies: \[ \cot(23^\circ + 22^\circ) = 1 \] ### Step 2: Use the cotangent addition formula The cotangent addition formula states: \[ \cot(A + B) = \frac{\cot A \cot B - 1}{\cot A + \cot B} \] Applying this to our angles: \[ \cot(23^\circ + 22^\circ) = \frac{\cot 23^\circ \cot 22^\circ - 1}{\cot 23^\circ + \cot 22^\circ} = 1 \] ### Step 3: Set up the equation From the cotangent addition formula, we have: \[ \frac{\cot 23^\circ \cot 22^\circ - 1}{\cot 23^\circ + \cot 22^\circ} = 1 \] This implies: \[ \cot 23^\circ \cot 22^\circ - 1 = \cot 23^\circ + \cot 22^\circ \] ### Step 4: Rearranging the equation Rearranging gives us: \[ \cot 23^\circ \cot 22^\circ - \cot 23^\circ - \cot 22^\circ = 1 \] ### Step 5: Adding 1 to both sides Now, we can add 1 to both sides: \[ \cot 23^\circ \cot 22^\circ - \cot 23^\circ - \cot 22^\circ + 1 = 2 \] ### Step 6: Factor the left-hand side The left-hand side can be factored: \[ (1 - \cot 23^\circ)(1 - \cot 22^\circ) = 2 \] ### Conclusion Thus, the value of the expression \((1 - \cot 23^\circ)(1 - \cot 22^\circ)\) is: \[ \boxed{2} \] ---
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VIKAS GUPTA (BLACK BOOK) ENGLISH-COMPOUND ANGLES-Exercise-5 : Subjective Type Problems
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  2. The value of expression (1-cot23^(@))(1-cot22^(@)) is equal to :

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  10. If the expression (sin theta sin2theta+sin3theta sin60theta+sin4theta...

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  12. If sin^(3)theta+sin^(3)(theta+(2pi)/(3))+sin^(3)(theta+(4pi)/(3))=a s...

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  14. If x=sec theta-tan theta and y="cosec"theta+cot theta," then " y-x-xy...

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  15. Prove that: cos18^0-sin18^0 = sqrt(2)sin27^0

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  19. If tan20^0+tan40^0+tan80^0-tan60^0= lambdasin40^0, find lambda.

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  20. If K^(@) lies between 360^(@) and 540^(@) and K^(@) satisfies the equa...

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