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In a triangle ABC , if tanA=2sin2Cand3co...

In a triangle ABC , if `tanA=2sin2Cand3cosA=2sinBsinC`, then C=

A

`(pi)/(8)`

B

`(pi)/(6)`

C

`(pi)/(4)`

D

`(pi)/(3)`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the given equations and use trigonometric identities to find the value of angle C in triangle ABC. ### Step 1: Start with the given equations We have two equations from the problem: 1. \( \tan A = 2 \sin 2C \) 2. \( 3 \cos A = 2 \sin B \sin C \) ### Step 2: Rewrite the second equation Using the identity \( 2 \sin B \sin C = \cos(B - C) - \cos(B + C) \), we can rewrite the second equation: \[ 3 \cos A = \cos(B - C) - \cos(B + C) \] Since \( A + B + C = \pi \), we can express \( B + C \) as \( \pi - A \): \[ 3 \cos A = \cos(B - C) + \cos A \] Rearranging gives us: \[ 3 \cos A - \cos A = \cos(B - C) \] \[ 2 \cos A = \cos(B - C) \tag{1} \] ### Step 3: Analyze the first equation From the first equation \( \tan A = 2 \sin 2C \), we can express \( \sin A \) in terms of \( \cos A \): \[ \sin A = \tan A \cdot \cos A = 2 \sin 2C \cdot \cos A \] ### Step 4: Use the double angle identity Using the double angle identity for sine, we have: \[ \sin 2C = 2 \sin C \cos C \] Thus: \[ \sin A = 4 \sin C \cos C \cos A \] ### Step 5: Substitute \( 2 \cos A \) From equation (1), we know \( 2 \cos A = \cos(B - C) \). Replacing \( 2 \cos A \) in our equation gives: \[ \sin A = \cos(B - C) \cdot \sin C \cos C \] ### Step 6: Use the sine rule We know that \( A + B + C = \pi \). Therefore, we can express \( B \) in terms of \( A \) and \( C \): \[ B = \pi - A - C \] Substituting this into our sine equation gives: \[ \sin A = \sin(3C - B) \] Using the sine identity, we can express this as: \[ \sin A = \sin(3C - (\pi - A - C)) = \sin(4C + A) \] ### Step 7: Set up the equation From the sine identity, we can equate: \[ \sin A = \sin(4C + A) \] This implies: \[ A = 4C + A \quad \text{or} \quad A + 4C = \pi \] Thus: \[ 4C = \pi - A \] ### Step 8: Substitute back into the triangle sum Using \( A + B + C = \pi \): \[ A + (\pi - A - C) + C = \pi \] This simplifies to: \[ 4C = \pi \] Thus: \[ C = \frac{\pi}{4} \] ### Final Answer The value of angle C is: \[ C = \frac{\pi}{4} \]
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