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Which of the following is arranged in de...

Which of the following is arranged in decreasing order of size?

A

`Mg^(2+) gt Al^(3+) gt O^(2-)`

B

`O^(2-) gt Mg^(2+) gt Al^(3+)`

C

`Al^(3+) gt Mg^(2+) gt O^(-)`

D

`Al^(3+) gt O^(2-) gt Mg^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the decreasing order of size for the given ions, we need to analyze the sizes of the ions based on their charges and the general trends in ionic sizes. ### Step-by-Step Solution: 1. **Identify the Ions**: We have three species to compare: \( \text{Mg}^{2+} \), \( \text{Al}^{3+} \), and \( \text{O}^{2-} \). 2. **Understand Ionic Sizes**: - **Cations** (positively charged ions) are smaller than their neutral atoms. The greater the positive charge, the smaller the cation. This is because a higher positive charge pulls the electrons closer to the nucleus, reducing the size. - **Anions** (negatively charged ions) are larger than their neutral atoms. The greater the negative charge, the larger the anion. This is because additional electrons increase electron-electron repulsion, causing the size to increase. 3. **Compare the Cations**: - **Magnesium Ion (\( \text{Mg}^{2+} \))**: This ion has a charge of +2. It is smaller than its neutral magnesium atom. - **Aluminum Ion (\( \text{Al}^{3+} \))**: This ion has a charge of +3. It is smaller than its neutral aluminum atom and smaller than \( \text{Mg}^{2+} \) because it has a higher positive charge. 4. **Compare the Anion**: - **Oxide Ion (\( \text{O}^{2-} \))**: This ion has a charge of -2. It is larger than its neutral oxygen atom because it has gained electrons, resulting in increased size due to electron-electron repulsion. 5. **Establish the Size Order**: - Since \( \text{O}^{2-} \) is an anion, it will be larger than both cations. - Between the cations, \( \text{Mg}^{2+} \) is larger than \( \text{Al}^{3+} \) because \( \text{Al}^{3+} \) has a higher positive charge. 6. **Final Order**: Therefore, the decreasing order of size is: \[ \text{O}^{2-} > \text{Mg}^{2+} > \text{Al}^{3+} \] ### Conclusion: The correct arrangement in decreasing order of size is: \[ \text{O}^{2-} > \text{Mg}^{2+} > \text{Al}^{3+} \]
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