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An element has successive ionization ent...

An element has successive ionization enthalpies as 940 (first),2080,3090,4140,7030,7870,16000 and 19500 kJ `mol^(-1)`. To which group of the periodic table does this element belong?

A

14

B

15

C

16

D

17

Text Solution

AI Generated Solution

The correct Answer is:
To determine the group of the periodic table to which the given element belongs based on its successive ionization enthalpies, we can follow these steps: ### Step 1: Analyze the Ionization Energies The given successive ionization enthalpies are: - 1st: 940 kJ/mol - 2nd: 2080 kJ/mol - 3rd: 3090 kJ/mol - 4th: 4140 kJ/mol - 5th: 7030 kJ/mol - 6th: 7870 kJ/mol - 7th: 16000 kJ/mol - 8th: 19500 kJ/mol ### Step 2: Identify the Large Jump Notice that there is a significant jump between the 6th and 7th ionization enthalpies (from 7870 kJ/mol to 16000 kJ/mol). This indicates that after removing the 6th electron, the next electron to be removed is from a much more stable electron configuration. ### Step 3: Relate to Electron Configuration The large increase in ionization energy suggests that the element has a stable electronic configuration after the removal of the first six electrons. In general, elements in Group 16 have the electronic configuration of ns²np⁴. - Removing the first electron (from ns²np⁴) gives ns²np³. - Removing the second electron gives ns²np². - Removing the third gives ns²np¹. - Removing the fourth gives ns² (which is stable). - Removing the fifth gives ns¹. - Removing the sixth gives a noble gas configuration (ns⁰). ### Step 4: Conclusion After the 6th ionization, the element reaches a noble gas configuration, which requires significantly more energy to remove an electron from a filled inner shell (1s²). This is consistent with the large jump in ionization energy observed. Thus, the element belongs to **Group 16** of the periodic table. ### Final Answer The element belongs to **Group 16** of the periodic table. ---
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