which of the following is the incorrect match for atom of element?

Options

A. `[Ar]3d^(5)4s^(2) to 4^(th)"period",6^(th)` group
B. `[Kr]4d^(10) to 5^(th" period, "12^(th)` group
C. `[Rn]6d^(1) 7s^(2) to 7^(th)` period, 3th group
D. `[Xe]4f^(14)5d^(2)6s^(2) to `6th period, 4th group

Explanation

To determine which of the given options is an incorrect match for the atom of an element based on its electron configuration, we will analyze each option step by step.

### Step 1: Analyze Option A
- **Configuration**: Argon, 3d5, 4s2
- **Maximum n value**: The highest principal quantum number (n) in the configuration is 4 (from 4s).
- **Period**: Since the maximum n value is 4, this element belongs to the **4th period**.
- **Group**: To find the group number, we add the number of d-electrons and s-electrons:
- d-electrons = 5 (from 3d5)
- s-electrons = 2 (from 4s2)
- Total = 5 + 2 = 7
- **Conclusion**: This element is in the **4th period and 7th group**. The option states 4th period and 6th group, which is **incorrect**.

### Step 2: Analyze Option B
- **Configuration**: 4d10, 5s0
- **Maximum n value**: The highest principal quantum number (n) is 5 (from 5s).
- **Period**: This element belongs to the **5th period**.
- **Group**:
- d-electrons = 10 (from 4d10)
- s-electrons = 0 (from 5s0)
- Total = 10 + 0 = 10
- **Conclusion**: This element is in the **5th period and 10th group**. The option states 5th period and 12th group, which is **incorrect**.

### Step 3: Analyze Option C
- **Configuration**: Radon, 6d1, 7s2
- **Maximum n value**: The highest principal quantum number (n) is 7 (from 7s).
- **Period**: This element belongs to the **7th period**.
- **Group**:
- d-electrons = 1 (from 6d1)
- s-electrons = 2 (from 7s2)
- Total = 1 + 2 = 3
- **Conclusion**: This element is in the **7th period and 3rd group**. The option matches correctly.

### Step 4: Analyze Option D
- **Configuration**: 4f14, 5d2, 6s2
- **Maximum n value**: The highest principal quantum number (n) is 6 (from 6s).
- **Period**: This element belongs to the **6th period**.
- **Group**:
- d-electrons = 2 (from 5d2)
- s-electrons = 2 (from 6s2)
- Total = 2 + 2 = 4
- **Conclusion**: This element is in the **6th period and 4th group**. The option matches correctly.

### Final Conclusion
The incorrect matches are found in **Option A** and **Option B**. Therefore, the answer to the question is that **Options A and B are incorrect matches**.

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