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Consider the order O^(2-) lt F^(-) lt Na...

Consider the order `O^(2-) lt F^(-) lt Na^(+) lt Mg^(2+)`. Then correct statement(s) is/are :

A

Increasing order of `Z_(eff)`.

B

Increasaing order of size

C

Increasing order of I.E

D

Increasing order of E.A

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The correct Answer is:
To analyze the order \( O^{2-} < F^{-} < Na^{+} < Mg^{2+} \) and determine the correct statements regarding effective nuclear charge (Z_eff), size, ionization energy, and electron affinity, we can follow these steps: ### Step 1: Understand the Species - Identify the species involved: - \( O^{2-} \): Oxygen ion with a charge of -2 (gains 2 electrons). - \( F^{-} \): Fluorine ion with a charge of -1 (gains 1 electron). - \( Na^{+} \): Sodium ion with a charge of +1 (loses 1 electron). - \( Mg^{2+} \): Magnesium ion with a charge of +2 (loses 2 electrons). ### Step 2: Determine the Number of Electrons and Protons - Count the protons and electrons for each ion: - \( O^{2-} \): 8 protons, 10 electrons. - \( F^{-} \): 9 protons, 10 electrons. - \( Na^{+} \): 11 protons, 10 electrons. - \( Mg^{2+} \): 12 protons, 10 electrons. ### Step 3: Analyze the Ionic Sizes - The size of the ions generally decreases with an increase in positive charge and increases with an increase in negative charge due to electron-electron repulsion. - Therefore, the order of ionic sizes is: - \( O^{2-} > F^{-} > Na^{+} > Mg^{2+} \) - This means the order given in the question is actually the decreasing order of size. ### Step 4: Evaluate the Effective Nuclear Charge (Z_eff) - The effective nuclear charge increases with the number of protons while the number of electrons remains constant. - Since the order of protons is \( 8 < 9 < 11 < 12 \), the effective nuclear charge also increases in the same order: - \( O^{2-} < F^{-} < Na^{+} < Mg^{2+} \) ### Step 5: Analyze Ionization Energy - Ionization energy is inversely related to the size of the ion. As size decreases, ionization energy increases. - Since the size order is \( O^{2-} > F^{-} > Na^{+} > Mg^{2+} \), the order of ionization energy will be: - \( O^{2-} < F^{-} < Na^{+} < Mg^{2+} \) (increasing order). ### Step 6: Analyze Electron Affinity - Electron affinity generally increases with decreasing size and increasing effective nuclear charge. - Thus, the order of electron affinity will also follow the same increasing order: - \( O^{2-} < F^{-} < Na^{+} < Mg^{2+} \). ### Conclusion Based on the analysis: 1. **Increasing order of Z_eff**: Correct 2. **Increasing order of size**: Incorrect (it's decreasing) 3. **Increasing order of ionization energy**: Correct 4. **Increasing order of electron affinity**: Correct ### Final Answer The correct statements are: 1, 3, and 4. ---

To analyze the order \( O^{2-} < F^{-} < Na^{+} < Mg^{2+} \) and determine the correct statements regarding effective nuclear charge (Z_eff), size, ionization energy, and electron affinity, we can follow these steps: ### Step 1: Understand the Species - Identify the species involved: - \( O^{2-} \): Oxygen ion with a charge of -2 (gains 2 electrons). - \( F^{-} \): Fluorine ion with a charge of -1 (gains 1 electron). - \( Na^{+} \): Sodium ion with a charge of +1 (loses 1 electron). - \( Mg^{2+} \): Magnesium ion with a charge of +2 (loses 2 electrons). ...
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