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If heat of solution for AB(s) is -0.95xx...

If heat of solution for AB(s) is `-0.95xx10^(x)` kcal/mol and lattice energy for `AB(s)` is 700 kcal/mol and hydration energy for `A^(+)(g)` is -1000 kcal/mol and `B^(-)(g)` is -650 kcal/mol then calculate value of x.

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Verified by Experts

The correct Answer is:
3
`-0.95xx10^(x)=700-1000-650`
`-0.95xx10^(x)=-950`
x=3
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